4k^2-28=6k

Solution for 4k^2-28=6k equation:

4k^2-28=6k

We move all terms to the left:

4k^2-28-(6k)=0

a = 4; b = -6; c = -28;
Δ = b2-4ac
Δ = -62-4·4·(-28)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-22}{2*4}=\frac{-16}{8}
=-2
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+22}{2*4}=\frac{28}{8}
=3+1/2
$